Potential due to System of Charges

Two charges ${\mathrm{q}}_1=12\times {10}^{-9}\mathrm{C}$ and ${\mathrm{q}}_2=-12\times {10}^{-9}\mathrm{C}$ are placed $10\mathrm{cm}$ apart. The potential at point $\mathrm{A}$ between them at a distance $6\mathrm{cm}$ from ${\mathrm{q}}_1$ on the line joining the two charges will be

Two concentric thin conducting spherical shell of radii $a$ and $b\left(a>b\right)$ having charges $Q_1$ and $Q_2$ respectively. The electrostatic potential at point $P$ at distance $c$ from their common centre will be

$\left(K=\frac{1}{4\pi {\epsilon }_0}\& b<c<a\right)$

$PQRS$ is a square of side $1 \mathrm{m}$. Faqs changes $+10nc$,$-20nc$,$+30nc$ and $+20\mathrm{nc}$ are placed at the corners $PQRS$ respectively calculate the electric potential at that intersection of diagonal is

Three point charges $2\mu \mathrm{C},-4\mu \mathrm{C}$ and $8\mu \mathrm{C}$ are placed at the three vertices of an equilateral triangle of side length $10\mathrm{cm}$. The potential at the centre of triangle is

An uncharged conductor has two spherical cavities of radius $r_1$ and $r_2$ two point charges $q_1$ and $q_2$ are placed at centres of cavities. Potential at the surface of conductor is $V_0$, then potential at point $P$ will be :-

Two point charges $q$ and $-2q$ are located at $\left(a, 0,0\right)$ and $\left(0,0,0\right)$ respectively. Assume that the potential $V$ is vanishing at infinity. The correct statement about the $V=0$ surface (at finite distance) is:

The electric potential at point P owing to two or more point charges does not depend upon the distance between the point and the charge.

Determine the electric potential at point P owing to two point charges of charge $+Q$, one at a distance $R$ and the other at a distance $2R$.

A unit positive charge has to be brought from infinity to a midpoint between two charges $20 \mu C$ and $10 \mu C$ separated by a distance of $50 \mathrm{m}.$ How much work will be required?

Three charges $1 \mathrm{\mu C}, 2 \mathrm{\mu C}$ and $3 \mathrm{\mu C}$ respectively are placed on the vertices of an equilateral triangle of $1000 \mathrm{m}$ side. Calculate the electric potential at the centre of the triangle.

Four charges each $2 \mathrm{\mu C}$ is placed on four corners of a square of side $2\sqrt{2} \mathrm{m}$. Find the potential at the centre of square. 

A charge of $5 \mathrm{\mu C}$ is placed on each of the vertices of a regular hexagon of side $10 \mathrm{cm}$, Find the electric potential at the centre of hexagon.

Two point charges, $3\times {10}^{-8} \mathrm{C}$ and $-2\times {10}^{-8} \mathrm{C}$ are $15 \mathrm{cm}$ apart. At what points on the line joining the charges the electric potential is zero? Assume the electric potential to be zero at infinity.

Four charges, $100 \mathrm{\mu C},-50 \mathrm{\mu C},20 \mathrm{\mu C}$ and $-60 \mathrm{\mu C}$ respectively are placed on four corners of a square of edge $\sqrt{2} \mathrm{m}$. Find the electric potential at the centre of square.

For the arrangement of charges as shown in adjoining diagram, the work done in moving a  $1 \mathrm{C}$ charge from $\mathrm{P}$ to $\mathrm{Q}$ (in joule) is

Two point charges of $+10 \mu \mathrm{C}$ and $+20 \mu \mathrm{C}$  are placed in free space $2 \mathrm{cm}$ apart. Find the electric potential at the middle point of the line joining the two charges.

Three charges $-Q$, $Q$ and $-2Q$ are placed along a line as shown in the figure. The potential energy of the system is

The distance between two point charges is made $\frac{1}{4}$ of its initial value. The new potential energy between them will become

Cotyledons are also called-